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Trignometry question The value of ((sin 53/cos 37)/(cot 65/tan 25))

Trignometry question
The value of ((sin 53/cos 37)/(cot 65/tan 25))

Grade:12th pass

3 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
6 years ago
The answer is .As both values will get cancel out and we will get the answer as unity
PASUPULETI GURU MAHESH
126 Points
6 years ago
the  answer is 1
cot 65/tan(90-65)((sin 53/cos 37)/(cot 65/tan 25))=((sin 53/cos(90-53))/(
                                                            =((sin 53/sin 53)/(cot 65/cot 65)
                                                              =1
 
raj
384 Points
6 years ago
 
hello,
the solution is:
=(sin53/cos37)into(cos65/sin65)into(cos25/sin25)=1
the answer is 1 for the given solution............

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