Theta=3*alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , a*cosec(alpha)-b*sec(alpha)

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Aditya Gupta · Answer

Kindly repost the question with a picture as it is not clear whether the under root sign is on a square or on whole of a square + b square .

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Theta=3alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , acosec(alpha)-b*sec(alpha)

Theta=3alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , acosec(alpha)-b*sec(alpha)

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Theta=3*alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , a*cosec(alpha)-b*sec(alpha)

Theta=3*alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , a*cosec(alpha)-b*sec(alpha)

1 Answers

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Theta=3alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , acosec(alpha)-b*sec(alpha)

Theta=3alpha And sin(theta)= a/√a^2+b^2 Then the value of the expression , acosec(alpha)-b*sec(alpha)