The values of x (0 ≤ x ≤ π) satisfying the equation sec2x + (1 − √3)tanx − (√3 + 1) = 0 are
The values of x (0 ≤ x ≤ π) satisfying the equation sec2x + (1 − √3)tanx − (√3 + 1) = 0 are
bonsai , 10 Years ago
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Trigonometry> The values of x (0 ≤ x ≤ π) satisfying th...
1 Answerssiddharth gupta
Last Activity: 10 Years ago
put sec2x=1+tan2x in the above eqn.so it becomes tan2x+(1-(3)1/2)tanx-(3)1/2=0.solve this quadratic to obtain x=135 and 60 degrees.
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