The values of x (0 ≤ x ≤ π) satisfying the equation sec²x + (1 − √3)tanx − (√3 + 1) = 0 are

Question

The values of x (0 ≤ x ≤ π) satisfying the equation sec 2 x + (1 − √3)tanx − (√3 + 1) = 0 are

siddharth gupta · Answer

put sec 2 x=1+tan 2 x in the above eqn.so it becomes tan 2 x+(1-(3) 1/2 )tanx-(3) 1/2 =0.solve this quadratic to obtain x=135 and 60 degrees.

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The values of x (0 ≤ x ≤ π) satisfying the equation sec 2 x + (1 − √3)tanx − (√3 + 1) = 0 are

The values of x (0 ≤ x ≤ π) satisfying the equation sec²x + (1 − √3)tanx − (√3 + 1) = 0 are

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The values of x (0 ≤ x ≤ π) satisfying the equation sec 2 x + (1 − √3)tanx − (√3 + 1) = 0 are

The values of x (0 ≤ x ≤ π) satisfying the equation sec2x + (1 − √3)tanx − (√3 + 1) = 0 are

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The values of x (0 ≤ x ≤ π) satisfying the equation sec²x + (1 − √3)tanx − (√3 + 1) = 0 are