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The summation of the given expression from n=1 to infinity is equal to(A) 3pi/4(B)pi/2

The summation of the given expression from n=1 to infinity is equal to(A) 3pi/4(B)pi/2

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Grade:11

1 Answers

Srilekha
16 Points
5 years ago
n^4-2n^2+2=(n^2-2n+1)(n^2+2n+1)+1Now conver it into tan^-1(A-B/1+AB)= TAN^-1(A)-TAN^-1(B)Then it gets converted to tan^-1(infinity)-tan^-1(0)= pi/2

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