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`        The ratio of the area of a regular polygon of n sides inscribed in a circle to that of the polygon of n sides and of perimeter equal to that of the circle are in the ratio ofans:tan(pi/n):(pi/n) `
2 years ago

```							The Area of the regular polygon inscribed in a Circle of radius r would be n sin(pie/n)cos(pie/n) r2. Now the second polygone has perimeter = 2pie.r and its Area would be r2. n sin(pi)/n cos(pi)/n and Area of the polygon with perimeter = Circle would be a2 n tan(pi)/n. where a is apothem. a = s/2tan(pi)/n = 2pi. r /2ntan(pi)/n= pi. r/2n tan(pi)/n So Area would be (pi. r/2n tan(pi)/n)2. n. tan(pi)/n. = [((pi)2.r2)/4 n2 tan2(pi)/n] *[n. tan(pi)/n]So the ratio would be = [n sin(pie/n)cos(pie/n) r2]/[ ((pi)2.r2)/4 n2tan2(pi)/n] *[n. tan(pi)/n] = [sin2(pi)/n]/(pi/n)2
```
2 years ago
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