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The question is there in the picture . Please help me by giving the solution to the problem .

Sreejoni . , 6 Years ago
Grade 11
anser 1 Answers
sachin kumar

Last Activity: 6 Years ago

asin\Theta -bcos\Theta =4
acos\Theta +bsin\Theta =3
take square both eq.and both side
eq. will be
a^2cos^2\Theta +b^2sin^2\Theta +absin2\Theta =9
we know that   : 2absin\Theta cos\Theta =absin2\Theta
a^2sin^2\Theta +b^2cos^2\Theta -absin2\Theta =16 
now you have to add these eq.
after adding these eq.
a^2(sin^2\Theta +cos^2\Theta) +b^2(sin^2\Theta +cos^2\Theta )=25
we know that : [sin^2\Theta +cos^2\Theta=1]
a^2+b^2=25

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