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The greatest angle of a cyclic quadrilatral is double the Least and difference of other two angles is 30 degree.find the angles
Let ABCD be quadrilateral.Now Sum of opposite angles of a cyclic quadrilateral is equal to 180 degree.therefore if angle A is greatest then C must be Least. A + C = 180Also A = 2C Therefore angle C = 60 degrees and angle A = 120 degrees Also B+D = 180 Let B – D = 30 Hence angle B = 105 degrees and Angle D = 75degreeTherefore Angles are 30 , 60 , 105 and 75 degrees
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