 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
the genderal solution of acosX+bsinX=c where a,b,c are constants

```
2 years ago

```							a cos x+b sin x= c , divide both sides by(a^2+b^2)^1/2.a/(a^2+b^2)^1/2.cos x+b/(a^2+b^2)^1/2.sin x=c/(a^2+b^2)^1/2.Let a/(a^2+b^2)^1/2=sin A , then b/(a^2+b^2)^1/2=cosAsinA.cos x+cos A.sin x=c/(a^2+b^2)^1/2sin (A+x)= c/(a^2+b^2)^1/2A+x=sin inverse c/(a^2+b^2)^1/2x=sin inverse c/(a^2+b^2)^1/2-Ax=sin inverse c/(a^2+b^2)^1/2 - sin inverse a/(a^2+b^2)^1/2.
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions