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The equation 4 ( sin x cos 3 x – cos x sin 3 x + 1) = 3 has the general solution: (n pi / 4) + ( 8 /pi) ( n pi/ 2) + ( 3 pi /8) n pi (+/– ) (5 pi / 8) (n pi/4) + ( 7 pi / 4)

The equation 4 ( sin x cos3x – cos x sin3x + 1) = 3 has the general solution:
  1. (n pi / 4) + ( 8 /pi)
  2. ( n  pi/ 2) + ( 3 pi /8)
  3.  n pi (+/– ) (5 pi / 8)
  4. (n pi/4) + ( 7 pi / 4)

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
4 sin x cos x (cos^2 x – sin^2 x) = 3 – 4
 
2 sin 2x cos 2x = – 1
 
sin 4x = – 1
 
hence
 
4x = 2n * pi + 3pi/2
 
x = n * pi / 2 + 3 * pi /8

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