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The equation 4 ( sin x cos 3 x – cos x sin 3 x + 1) = 3 has the general solution: (n pi / 4) + ( 8 /pi) ( n pi/ 2) + ( 3 pi /8) n pi (+/– ) (5 pi / 8) (n pi/4) + ( 7 pi / 4)
Dear student 4 sin x cos x (cos^2 x – sin^2 x) = 3 – 4 2 sin 2x cos 2x = – 1 sin 4x = – 1 hence 4x = 2n * pi + 3pi/2 x = n * pi / 2 + 3 * pi /8
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