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```
tan ( x+y) = a+b , tan (x-y ) = a-b , then show a tanx - b tany= a^2 - b^2 .
tan ( x+y) = a+b , tan (x-y ) = a-b , then show a tanx - b tany= a^2 - b^2 .

```
5 years ago

vsujji
17 Points
```							[a+b][a-b]=tan[x+y].tan[x-y]a^2-b^2=[tan^2x-tan^2y]/1-tan^2xtan62y].......................................................equation 1         tan[x+y]+tan[x-y]=2a    …......we get    2a = [2tanx+2tanxtan^2y]/[1-tan^2xtan^2 y]                          atanx=[tan^2x+tan^2xtan^2y]/[1-tan^2xtan^2y]similarly  btany = [tan^2y+tan^2xtan^2y]/[1-tan^2xtan^y]      atanx-btany = [tan^2x-tan^2y]/[1-tan^2xtan^2y]..........................................equation 2from equation 1 and 2 weget  atanx-btany=a^2-b^2
```
5 years ago
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• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions