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Tan( pi/3 + x)* tan( pi /3-x) = 2 cos2x +1/ 2 cos2x -1
tan(A+B).tan(A-B)={sin(A+B).sin(A-B)}/{cos(A+B).cos(A-B)}use formlas to gettan(A+B).tan(A-B)={(cos(B))^2-(cos(A))^2}/{(cos(B))^2-(sin(A))^2}on RHSuse cos2x=2(cos(x))^2-1 to get the LHS
tan(A+B).tan(A-B)={sin(A+B).sin(A-B)}/{cos(A+B).cos(A-B)}
use formlas to get
tan(A+B).tan(A-B)={(cos(B))^2-(cos(A))^2}/{(cos(B))^2-(sin(A))^2}
on RHS
use cos2x=2(cos(x))^2-1 to get the LHS
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