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```
Tan( pi/3 + x)* tan( pi /3-x) = 2 cos2x +1/ 2 cos2x -1
Tan( pi/3 + x)* tan( pi /3-x) = 2 cos2x +1/ 2 cos2x -1

```
2 years ago

na batau
17 Points
```							tan(A+B).tan(A-B)={sin(A+B).sin(A-B)}/{cos(A+B).cos(A-B)}use formlas to gettan(A+B).tan(A-B)={(cos(B))^2-(cos(A))^2}/{(cos(B))^2-(sin(A))^2}on RHSuse cos2x=2(cos(x))^2-1 to get the LHS
```
2 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions