tan(alfa+beta)=1/2,tan(alfa-bata)=1/3, then find the value of tan2alfa
Ritik , 8 Years ago
Grade 12th pass
Trigonometry> tan(alfa+beta)=1/2,tan(alfa-bata)=1/3, th...
1 Answers
poojitha
Last Activity: 8 Years ago
tan[(alfa+beta)+(alfa-beta)] = [tan(alfa+beta)+tan(alfa-beta)]/[1-tan(alfa+beta).tan(alfa-beta)] =(1/2+1/3)/(1-1/2.1/3) = (5/6)/(5/6) = 1 [tan2alfa=tan(alfa+beta+alfa-beta)]
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