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Tan(a+b)-X and tan(a-b)=y find the value of tan2a and tan2b
tan2A = tan [ (A+B) + (A-B) ]Now, the formula.. tan (x+y) = tan x + tan y / 1-tan x.tan ySo,tan2A = [ tan (A+B) + tan (A-B) ] / 1 - tan (A+B). tan (A-B)Substitue.. tan (A+B) = x and tan (A-B) = ySo,= x + y / 1-xySame is the way for tan2Btan2B = tan [ (A+B) - (A-B) ]tan ( x - y ) = tan x - tan y / 1 + tan x.tan ySo,tan2B = [ tan (A+B) - tan (A-B) ] / 1+tan (A+B).tan (A-B)= x - y / 1+ xy
tan2A = tan [ (A+B) + (A-B) ]
Now, the formula.. tan (x+y) = tan x + tan y / 1-tan x.tan y
So,
tan2A = [ tan (A+B) + tan (A-B) ] / 1 - tan (A+B). tan (A-B)
Substitue.. tan (A+B) = x and tan (A-B) = y
= x + y / 1-xy
Same is the way for tan2B
tan2B = tan [ (A+B) - (A-B) ]
tan ( x - y ) = tan x - tan y / 1 + tan x.tan y
tan2B = [ tan (A+B) - tan (A-B) ] / 1+tan (A+B).tan (A-B)
= x - y / 1+ xy
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