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tan a and tan b are the toots of the equation
X² - pX + q = 0 the nthe value of sin²(a+b)

vinit arora , 6 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 6 Years ago

Dear Vinit
 
tan a + tanb = p
tan a * tan b = q
 
 
tan(a+b) = tan a + tan b / (1 – tan a tanb)
 
 = p/ 1 – q
 
tan(a+b) = p /(1 – q)
 
sin (a+b) = p / \sqrt(p2 + (1 -q)2)
 
hence
 
sin2 (a+b) = p2 / (p2 + (1 -q)2)

Deepak Kumar Shringi

Last Activity: 6 Years ago

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