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Tan(45+A) - tan(45-A) ÷ tan(45+A) + tan(45-A) = sin2A

Tan(45+A) - tan(45-A) ÷ tan(45+A) + tan(45-A) = sin2A

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Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
Dear Aman
 
tan (45+ A) = (1 + tan A)/ (1 – tanA)
 
tan (45 – A) = (1 – tanA)/ (1 + tanA)
 
Now use this in LHS
 
(1+ tanA)^2  – (1 – tanA)^2 / (1+tanA)^2 + ( 1 – tan A)^2
 
 = 4tanA / 2 + 2 tan^2 A = 2 tanA /(1+tan2A)
 
 = sin 2A

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