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Grade: 12th pass

                        

Solve this: 1.tantheta / 1-tan square theta = sintheta sin (90-theta) / 2sinsquare (90-theta)-1 2. 1 / (cosec theta – cot theta) – 1 / sintheta = 1/sintheta – 1/(cosec theta+cottheta) 3.(cotsquare theta + secsquare theta) / (tansquare theta + cosec square theta) = (sintheta costheta) (tan theta + cot theta)

3 years ago

Answers : (1)

Drishtant Mishra
13 Points
							And 1=LHSReplacing theta by "x" for ease in typing tanx/1-tan^2x=sinx/cosx/1-sin^2x/cos^2sinx/cosx/cos^2-sin^2x/cos^2Sinx.cosx/cos2x =LHS (Since cos^2-sin^2x=cos2x) RHSsinx.sin(90-x)/2sin^2 (90-x)-1sinx.cosx/2cos^2x-1 =RHShence RHS=LHSsinx.cosx/cos2x
						
3 years ago
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