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Solve the following problem, find out the value of theta Cosec theta = 1+ cot theta
Cosecθ = 1 + Cotθ⇒1/Sinθ = 1 + Cosθ/Sinθ⇒1/Sinθ = (Sinθ + Cosθ)/Sinθ⇒Sinθ + Cosθ = 1Squaring both sides,⇒Sin2θ + Cos2θ + 2SinθCosθ = 1⇒1 + Sin2θ = 1⇒Sin2θ = 0⇒2θ = nπ⇒θ = nπ/2
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