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solve for x tan^-1(x+2) + tan^-1(x-2) =tan^-1(8/79), x>0

solve for x
tan^-1(x+2) + tan^-1(x-2) =tan^-1(8/79), x>0

Grade:12

1 Answers

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
8 years ago
taking tan both sides

(x+2+x-2)/(1-(x+2)(x-2))=8/79

79x= 8(1-x2+4)
8x2+79x+40=0

solve this quardatic for value of x
sher mohammad
b.tech, iit delhi

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