0

Guest

Courses New

solve for x sin[cot^-1(x+1)]=cos[tan^-1(x)] when i write cot inverse x as pi by 2 – tan inverse x. x gets cancelled

solve for x
sin[cot^-1(x+1)]=cos[tan^-1(x)]
when i write cot inverse x as pi by 2 – tan inverse x. x gets cancelled

Grade:12

1 Answers

Chandrasekar Ram J
11 Points
5 years ago
cot^-1(x+1) = sin^-1(1/sqrt(1+(1+x)²)
tan^-1(x) = cos^-1(1/sqrt(x²+1))
hence,  sin(cot^-1(x+1))    = cos(tan^-1(x))
             sin(sin^-1(1/sqrt(1+(1+x)²))=cos(cos^-1(1/sqrt(x²+1)))
             1/sqrt(1+(1+x)²=1/sqrt(x²+1)
      ==> 1+(1+x)² = x² + 1
     ==> 1 + 1 + x² + 2x = x² + 1
     ==>  2x = -1
    ==> x = – 1/2

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More