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sinAsin(A+2B)-sinBsin(B+2A)=sin(A-B)sin(A+B) Prove that:

sinAsin(A+2B)-sinBsin(B+2A)=sin(A-B)sin(A+B)
Prove that:

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear Abhiraj
 
½ [cos (- 2B ) – cos (2A + 2B) – cos(- 2A) + cos (cos 2A + 2B)]
 
½ [cos 2B – cos 2A]
 
½ [2 sin^2 A – 2 sin^2 B]
 
sin^2 A – sin^2B
 
sin (A + B) sin(A – B)

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