sina+sinb+sinc=0 and cosa+csb+cosc=0 then cos(a+b)+cos(b+c)+cos(a+c)=

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Arun · Answer

Dear student I think that you have done a mistake in writing. please check that it should be cos (A – B) + cos(B – C) + cos (C – A) Regards Arun

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sina+sinb+sinc=0 and cosa+csb+cosc=0 then cos(a+b)+cos(b+c)+cos(a+c)=

sina+sinb+sinc=0 and cosa+csb+cosc=0 then cos(a+b)+cos(b+c)+cos(a+c)=

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sina+sinb+sinc=0 and cosa+csb+cosc=0 then cos(a+b)+cos(b+c)+cos(a+c)=

sina+sinb+sinc=0 and cosa+csb+cosc=0 then cos(a+b)+cos(b+c)+cos(a+c)=

1 Answers

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