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SinA+Sin B =root 3 (cos B -cos A) sin3A+sin3B isequal to

SinA+Sin B =root 3 (cos B -cos A) sin3A+sin3B isequal to

Grade:9

1 Answers

Arun
25763 Points
3 years ago
sinA + sinB = root(3) cosB - root(3)cosA

Divide by 2 both side

sinA / 2  + sinB / 2  = root(3).cosB/2 - root(3).cosA/2

1/2 . sinA  + root(3)/2 .cosA  =  root(3)/2 . cos(B)  - 1/2 . sin(B)

sin(A + 60)  = cos(B + 30)  =>  sin(A+60) = sin ( 60 - B )

so finaly  A + 60 = 60 - B

so A = -B

Therefore   Sin3B + sin3A  =  0 

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