Sina+cosb=1/√2 & cosa+sinb=√2/√3 then find the value of : (1) sin(a+b) (2) tan(a-b/2)
Atharva , 9 Years ago
Grade 11
Trigonometry> Sina+cosb=1/√2 & cosa+sinb=√2/√3 then fin...
1 AnswersVikas TU
Sina+cosb=1/√2
Sina = 1/√2 – cosb
squaring both sides,
(sina)^2 = 1/2 + (cosb)^2 – 2cosb/√2
1 – (cosa)^2 = 1/2 + (cosb)^2 – 2cosb/√2
1/2 – (cosa)^2 = (cosb)^2 – 2cosb/√2.................(1)
This is the eqn. 1
Do it same squaring method in cosa+sinb=√2/√3
and bring the final eqn. in cosa and cosb terms
then after solve those eqns. andd get cosa and cosb values.
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