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Sin2A+sin2C+sin2B= 2(sinA+sinB+sinC)(1+cosA+cosB+cosC)

Sin2A+sin2C+sin2B= 2(sinA+sinB+sinC)(1+cosA+cosB+cosC)

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
5 years ago
Dear student

Kindly specify what needs to be done with the equation

ie do you wish to simplify or proof etc

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