Sin(x-y)=cos(x+y)=1/2 =Sin(x-y)=1/2 =Sin(x-y)=30° =(X-y)=30°----(1) Cos(x+y)=1/2 =Cos(x+y)=60° =(X+y)=60°-----(2) 1or2---- (X-y)=30° (X+y)=60°

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Saurabh Koranglekar · Answer

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Abdul Rahman · Answer

sin(x-y)=1/2 sin(x-y)= sin30 0 x-y =30 0 --------1 and cos(x+y) =1/2 cos(x+y) = cos60 0 x+y = 60 0 ----------2 on adding 1 & 2, we get, 2x = 90 0 x = 45 0 and on subtracting 1 & 2, we get, -2y = -30 0 y = 15 0

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Sin(x-y)=cos(x+y)=1/2 =Sin(x-y)=1/2 =Sin(x-y)=30° =(X-y)=30°----(1) Cos(x+y)=1/2 =Cos(x+y)=60° =(X+y)=60°-----(2) 1or2---- (X-y)=30° (X+y)=60°

Sin(x-y)=cos(x+y)=1/2
=Sin(x-y)=1/2
=Sin(x-y)=30°
=(X-y)=30°----(1)
Cos(x+y)=1/2
=Cos(x+y)=60°
=(X+y)=60°-----(2)
1or2----
(X-y)=30°
(X+y)=60°

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Sin(x-y)=cos(x+y)=1/2 =Sin(x-y)=1/2 =Sin(x-y)=30° =(X-y)=30°----(1) Cos(x+y)=1/2 =Cos(x+y)=60° =(X+y)=60°-----(2) 1or2---- (X-y)=30° (X+y)=60°

Sin(x-y)=cos(x+y)=1/2 =Sin(x-y)=1/2=Sin(x-y)=30°=(X-y)=30°----(1)Cos(x+y)=1/2=Cos(x+y)=60°=(X+y)=60°-----(2)1or2----(X-y)=30°(X+y)=60°

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Sin(x-y)=cos(x+y)=1/2
=Sin(x-y)=1/2
=Sin(x-y)=30°
=(X-y)=30°----(1)
Cos(x+y)=1/2
=Cos(x+y)=60°
=(X+y)=60°-----(2)
1or2----
(X-y)=30°
(X+y)=60°