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Sin(a+b+c) / CosA CosB CosC = tanA + tanB + tanC - tanA tanB tanC. Prove.

Sin(a+b+c) / CosA CosB CosC = tanA + tanB + tanC - tanA tanB tanC. Prove.

Grade:11

1 Answers

rohanmathematics
26 Points
3 years ago
MY NAME IS ROHAN CHAURASIA I AMGIVING JUST THIS ANSWER BY TELLING YOU THAT .=Trignometry is basicallly a mind and tricky game if you applied that trick you will definately get a answer
Sin(A+B)Cos(c) +Cos(A+B)Sin(c)
__________________________=     CosCSinACosB + CosASinBCosC + CosACosBSinC-SinASinBSinC
CosA CosB CosC                               _____________________________________________________________
                                                                          CosA CosB CosC
                                                     =     TanA + TanB + TanC -TanA TanB TanC

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