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Grade: 10
        
SIN 90=1, COS 90= 0, THEN TAN45, SEC30, SEC90, COSEC90,  TAN 45, COSEC 30, TAN 0, COT 90,COT45, TAN30 ,TAN180M, COSEC 270
 
 
one month ago

Answers : (1)

Saurabh Koranglekar
askIITians Faculty
1466 Points
							TAN45 = 1;

SEC30 = 2/(3^0.5)

SEC90 = not defined

COSEC90 = 1

COSEC 30 = 2

TAN 0 =0

COT 90 =0

COT45 = 1

TAN30 = 1/(3^0.5),

TAN180 = 0

COSEC 270= -1
one month ago
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