 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Sin*4x/2 + cos*4x/3 = 1/5 show that sin*8x/8+cos*8x/27=1/125 trignometry`
one year ago

```							3sin^4x +2cos^4x=6/53sin^4x +2(1-sin^2x)^2=6/53sin^4x +2sin^4x-4sin^2x+2=6/55sin^4x -4sin^2x +2=6/525sin^4x -20sin^2x+4=0(5sin^2x-2)(5sin^2x-2)=0sin^2x =2/5 ,   sin^8x=(2/5)^4cos^2x=1-2/5=3/5     , cos^8x=(3/5)^4Putting the values of sin^8x/8 and cos ^8x/27 we will get 1/125
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions