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sin 2 42-sin 2 84=

sin242-sin284=

Grade:11

1 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
7 years ago
Hello student, Please find the answer to your question below

sin242-sin284
= (sin42-sin84)(sin42+sin84)
use the following formulas :-
SinC + SinD = 2Sin[(C+D)/2]Cos[(C-D)/2]

SinC - SinD = 2Cos[(C+D)/2]Sin[(C-D)/2]

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