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(sec A + tan A) (1 – sin A) = (A) sec A (B) sin A (C) cosec A (D) cos A
Dear StudentOption (D) is correct.Justification:We know that,Sec A= 1/cos ATan A = sin A / cos ANow,substitute the above values in the given problem,we get(secA + tanA) (1 - sinA)= (1/cos A + sin A/cos A) (1 - sinA) = (1+sin A/cos A) (1 - sinA)= (1 - sin^2 A)/cos A= cos^2 A/cos A= cos ATherefore, (secA + tanA) (1 - sinA) = cos A i.e Option (D)Thanks
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