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prove the following: tan3A*tan2a*tanA = tan3A-tan2A-tanA co(A+15)-tan(A-15) =4cos2A/1+2sin2A

prove the following:
  1. tan3A*tan2a*tanA = tan3A-tan2A-tanA
  2.  co(A+15)-tan(A-15) =4cos2A/1+2sin2A

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear Purva
 
Please ask only one question in one thread.
 
As we know
 
tan 3A = tan (2A+ A)
 
tan 3A = tanA + tan2A / 1 – tan A tan2A
 
tan 3A – tan A tan 2A tan3A = tan A + tan 2A
 
tan 3A – tan2A – tanA = tan 3A * tan 2A* tanA
 
hence proved

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