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Prove that sinAsinBsinC ≤ (3√3)/8 of A+B+C = 180°. Please help. Be quick.....

Prove that sinAsinBsinC ≤ (3√3)/8 of A+B+C = 180°. Please help. Be quick.....

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

It is based on AP >= GP concept

Kindly equate it putting all angles equal

Regards

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