Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

prove that sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=(1÷√2)sinA

prove that sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=(1÷√2)sinA

Grade:11

1 Answers

Jayanth Kasaraneni
50 Points
4 years ago
we know that sin2A-sin2B = sin (A+B)sin(A-B)
π/8 + a/2+π/8 - a/2) sin(π/8 + a/2-π/8+ a/2)sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=sin(
π/4) sin(a)=sin(
=(1/\sqrt{2} ) sina
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free