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Grade: 11
        prove that sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=(1÷√2)sinA
one year ago

Answers : (1)

Jayanth Kasaraneni
50 Points
							
we know that sin2A-sin2B = sin (A+B)sin(A-B)
π/8 + a/2+π/8 - a/2) sin(π/8 + a/2-π/8+ a/2)sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=sin(
π/4) sin(a)=sin(
=(1/\sqrt{2} ) sina
 
one year ago
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