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Prove that in a ∆ABC, (cos^2 (b-c)/2)/(b+c)^2 + (sin^2 (b-c)/2)/(b-c)^2 =1/a^2 Prove that in a ∆ABC, (cos^2 (b-c)/2)/(b+c)^2 + (sin^2 (b-c)/2)/(b-c)^2 =1/a^2
Hiiuse the cos and sin half angles formula in terms of sides of a triangle and just insert values over here you will get the answer
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