Prove that cotA + cotB + cotC >= 0, when A, B and C are angles of a triangle.
Prove that cotA + cotB + cotC >= 0, when A, B and C are angles of a triangle.
PV , 7 Years ago
Grade 11
Trigonometry> Prove that cotA + cotB + cotC >= 0, when ...
1 AnswersSubhashis
Last Activity: 7 Years ago
Since value of cot theta lies between 0and infinity...therefore..if we take the most minimum values of a b and c functioned as cot then also it would be greater than zero...i.e,0+0+0(cot a+cot b+cot c)=0...pd
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