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Grade: 11

                        

Plz help me with this question of definite integral

10 months ago

Answers : (3)

Arun
25359 Points
							
Dear student
 
We have to break limit from -1 to 0, 0 to 2
 
Hence from -1 to 0 (-x² dx) + from 0 to 2 (x² dx)
 
(-x³/3 )-10 + (x³/3)02
 
= 1/3 + 8/3 = 9/3 = 3
10 months ago
Aditya Gupta
2069 Points
							
aruns ans is wrong.
note that x|x| is an odd function.
so breal integral as:
∫ – 1 ro 1 x|x|dx  +  ∫1 to 2 x|x|dx
= 0 + ∫1 to 2 x*xdx
= x^3/3 | 1 to 2
= (8 – 1)/3
7/3
kindly approve :))
10 months ago
TEJA KRISHNA
42 Points
							
 
We have to break limit from -1 to 0, 0 to 2
 
Hence from -1 to 0 (-x² dx) + from 0 to 2 (x² dx)
 
(-x³/3 )-10 + (x³/3)02
 
= 1/3 + 8/3 = 9/3 = 3
               ALL THE BEST FOR UR EXAMS
10 months ago
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