×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Plz help me with this question of definite integral

```
10 months ago

Arun
25359 Points
```							Dear student We have to break limit from -1 to 0, 0 to 2 Hence from -1 to 0 (-x² dx) + from 0 to 2 (x² dx) (-x³/3 )-10 + (x³/3)02 = 1/3 + 8/3 = 9/3 = 3
```
10 months ago
2069 Points
```							aruns ans is wrong.note that x|x| is an odd function.so breal integral as:∫ – 1 ro 1 x|x|dx  +  ∫1 to 2 x|x|dx= 0 + ∫1 to 2 x*xdx= x^3/3 | 1 to 2= (8 – 1)/3= 7/3kindly approve :))
```
10 months ago
TEJA KRISHNA
42 Points
```							 We have to break limit from -1 to 0, 0 to 2 Hence from -1 to 0 (-x² dx) + from 0 to 2 (x² dx) (-x³/3 )-10 + (x³/3)02 = 1/3 + 8/3 = 9/3 = 3               ALL THE BEST FOR UR EXAMS
```
10 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions