Likith Narayan ss
Last Activity: 8 Years ago
(cos 8-sin8)/(cos 8+sin8) =(cos 8(1-sin 8/cos 8))/(cos 8(1+sin8/cos8))
by cancelling common cos 8 and writing tan 8=sin8/cos8
=(1-tan8)/(1+tan8)
writing 1as tan45
=(tan45-tan8)/(1+tan45*tan8)
which is in the form of (tanA-tanB)/(1+tanA*tanB)=tan(A-B)
=tan(45-8)
=tan(37)