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Grade: 12th pass

                        

Please give the solution of attached question .How we can find minimum and maximum value of these function.

2 years ago

Answers : (1)

Aditya Gupta
2065 Points
							

let sinx=s and cosx=c

we know that c^12

and s^2, s^4, s^6>=0

adding these inequalities, we get

(1 – c^12)+s^2+s^4+s^6>=0

or (1+s^2)(1+s^4)>=c^12

multiplying booth sides by c^2>=0,

c^2*(1+s^2)(1+s^4)>=c^12*c^2

or  (1 – s^2)(1+s^2)(1+s^4)>=c^14

 (1 – s^4)(1+s^4)>=c^14

 1 – s^8>=c^14

or c^14+s^8

or A

and as s^8, c^14>=0, adding we get 

s^8+c^12>=0

so, 

0

2 years ago
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