Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Please give the solution of attached question .How we can find minimum and maximum value of these function.
let sinx=s and cosx=cwe know that c^12and s^2, s^4, s^6>=0adding these inequalities, we get(1 – c^12)+s^2+s^4+s^6>=0or (1+s^2)(1+s^4)>=c^12multiplying booth sides by c^2>=0,c^2*(1+s^2)(1+s^4)>=c^12*c^2or (1 – s^2)(1+s^2)(1+s^4)>=c^14 (1 – s^4)(1+s^4)>=c^14 1 – s^8>=c^14or c^14+s^8or Aand as s^8, c^14>=0, adding we get s^8+c^12>=0so, 0
let sinx=s and cosx=c
we know that c^12
and s^2, s^4, s^6>=0
adding these inequalities, we get
(1 – c^12)+s^2+s^4+s^6>=0
or (1+s^2)(1+s^4)>=c^12
multiplying booth sides by c^2>=0,
c^2*(1+s^2)(1+s^4)>=c^12*c^2
or (1 – s^2)(1+s^2)(1+s^4)>=c^14
(1 – s^4)(1+s^4)>=c^14
1 – s^8>=c^14
or c^14+s^8
or A
and as s^8, c^14>=0, adding we get
s^8+c^12>=0
so,
0
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -