 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Please give the solution of attached question .How we can find minimum and maximum value of these function.

```
2 years ago

```							let sinx=s and cosx=cwe know that c^12and s^2, s^4, s^6>=0adding these inequalities, we get(1 – c^12)+s^2+s^4+s^6>=0or (1+s^2)(1+s^4)>=c^12multiplying booth sides by c^2>=0,c^2*(1+s^2)(1+s^4)>=c^12*c^2or  (1 – s^2)(1+s^2)(1+s^4)>=c^14 (1 – s^4)(1+s^4)>=c^14 1 – s^8>=c^14or c^14+s^8or Aand as s^8, c^14>=0, adding we get s^8+c^12>=0so, 0
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions