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please give me ans for the attached question see attach

VENKATA RAMANA , 8 Years ago
Grade 11
anser 2 Answers
Aamina

Last Activity: 8 Years ago

m = a cos3 \theta + 3a cos\theta sin2\theta
 
n =  a sin3  \theta + 3a cos2\theta sin\theta
 
m+n = a [ cos3 \theta + sin3 \theta + 3cos\theta sin2\theta +3 cos2\theta sin\theta ]
 
m+n =a [ cos\theta +sin\theta ]3
 
(m+n)2/3 = a2/3 { [cos\theta +sin\theta]3 }2/3
 
(m+n)2/3 = a2/3 [cos\theta +sin\theta]2 …..................(1)
 
(m+n)2/3 = a2/3 [1 + 2sin\theta cos\theta]
 
In the same way,
 
(m-n)2/3 = a2/3  [1 – 2sin\thetacos\theta]....................(2)
 
Adding (1) and (2)
 
(m+n)2/3 + (m-n)2/3  = a2/3 [1+2sin\thetacos\theta +1- 2sin\thetacos\theta]
 
                              = a2/3 [2]
 
                              =2a2/3
 
                              =2\sqrt[]{}3\sqrt{}a2
 
Hence option (D) is the answer.
 
HOPE THIS HELPS.

VENKATA RAMANA

Last Activity: 8 Years ago

thank u very much frnd...

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