MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
Please answer the question nd thanks in advance.the question number is 14 and has 3 parts .plese answer all the parts
11 months ago

Answers : (2)

Susmita
425 Points
							
Let me do any one for you.to learn,please do the rest yourself.if you face any problem then ask me again.
y=1+2sinx+3cosx
dy/dx=2cosx-6cosxsinx=2cosx(1-3sinx)
d2y/dx2=-2sinx(1-3sinx)+2cosx(-3cosx)
=-2sinx+6sin2x-6cos2x
for max or min dy/dx=0.
Either cosx=0 or sinx=1/3
Take cosx=0,then x=90,sinx=1.d2y/dx2=-2+6=8>0 
this is the condition for minima.
y=1+2=3(min)
Take sinx=1/3,cosx=root(1-sin2x)=2root2/3
d2y/dx2=-2/3+6/9-24/9=-2/3-18/9=-2/3-2=-8/2=-4
y=1+2/3+24/9=5/3+8/3=14/3
Hope you can do the rest.
 
11 months ago
Deepak Kumar Shringi
askIITians Faculty
4391 Points
							for all parts who have to find first of all differentiate the function and then find maxima and minima
im solving part b here
y=1+2sinx+3cos^2x
dy/dx=2cosx-6sinx cosx=2 cosx(1-3sinx)
dy/dx=0 for cosx=0 or sinx=1/3
when cosx=0 , sinx can be -1 or 1
so find now
y=1+2=3 when sinx=1
y=1-2=-1 when sinx=-1 minimum
y=14/3 when sinx=1/3 maximum
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details