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`        MAXIMUM value of sin^2(120+theta)+sun^2(120-theta) is `
one year ago

Saurabh Koranglekar
3161 Points
```
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one year ago
Arun
22962 Points
```							sin(t)^2 = (1/2) * (1 - cos(2t)) sin(120 + a)^2 + sin(120 - a)^2 => (1/2) * (1 - cos(2 * (120 + a))) + (1/2) * (1 - cos(2 * (120 - a))) => (1/2) * (1 - cos(240 + 2a) + 1 - cos(240 - 2a)) => (1/2) * (2 - (cos(240 + 2a) + cos(240 - 2a))) => 1 - (1/2) * (cos(240)cos(2a) - sin(240)sin(2a) + cos(240)cos(2a) + sin(240)sin(2a)) => 1 - (1/2) * (2 * cos(240) * cos(2a)) => 1 - cos(240) * cos(2a) cos(t) = 1 when t = 360 * k cos(t) = -1 when t = 180 + 360 * k 1 - cos(240) * (-1) => 1 + cos(240) => 1 - 1/2 => 1/2 1 - cos(240) * 1 => 1 - (-1/2) => 3/2 3/2 is the maximum
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions