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Log(tan18)+log(tan36)+log(tan54)+log(tan72)=?
Please say me the answer

Kruthik Reddy , 7 Years ago
Grade 11
anser 1 Answers
Ayushi nanda
log(tan 18)+log(tan 36)+log(tan 54)+log(tan 72)Using log(a)+log(b)+,,,=log(ab...), we getlog(tan 18)+log(tan 36)+log(tan 54)+log(tan 72)=log[tan 18.tan 36.tan 54.tan 72]=log[tan 18.tan 36.cot (90−54).cot (90−72)]=log[tan 18.tan 36.cot 36.cot 18]=log[tan 18.tan 36.1tan18.1tan 36]=log(1)=0 [Answer]
Last Activity: 7 Years ago
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