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Let sinx and siny be the root of the quadratic equation a sin^2 h + b sin h + c = 0 (a,b,c belongs to real number a unequal to zero ) such that sinx + 2siny = 1 , then the value of (a^2 + 2b^2 + 3ab + Ac) equals (A)0 (B)1 (C)2 (D)4
we see that sinx+siny= – b/a and sinx*siny=c/a, also given that sinx+2siny=1 or equivalently, siny=1+b/a and sinx=c/(a+b)now, sinx+siny= 1+b/a+c/(a+b)= – b/a so (a+2b)*(a+b)+ac=0or a^2+2b^2+3ab+ac=0option A is correct
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