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`         Let cosx + cosy = 1, find the range of values of sinx − siny.`
6 months ago

```							Dear student  cos x + cos y = 1means two casecase1.cos x= 1 and cos y = 0hence sinx = 0 and siny = ± 1hence sinx – sin y = ± 1 case2.cosx = 0 and cosy = 1hence sin x = ± 1 and sin y = 0 hence sinx – sin y = ± 1
```
6 months ago
```							dear charu, the ans provided by arun is totally WRONG. the correct ans is below:cosx + cosy = 1sinx − siny = ksquaring and addingk^2 + 1= cos^2x + cos^2y + 2cosxcosy + sin^2x + sin^2y – 2sinxsiny= 2 + 2cos(x+y)or k= ± sqrt (1+2cos(x+y))now, obviously k can be 0 when x= y= pi/3also, cos(x+y) is less than equal to 1or 2 cos(x+y) is less than equal to 2or 1+2 cos(x+y) is less than equal to 1+2= 3or sqrt (1+2 cos(x+y)) is less than equal to sqrt 3or |k| is less than equal to sqrt 3so, range of k is [–sqrt(3), sqrt(3)].kindly approve :))
```
6 months ago
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