MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        In triangle abs if tanA:tanB:tanC=1:2 :3 then a2 :b2 :c2=
one year ago

Answers : (2)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points
							Dear student,

tanA =Δ/ s (s-a)
tanB =Δ/ s (s-b)
tanC =Δ/ s (s-c)
Where s = a+b+c/2

henceΔ/ s (s-a) :Δ/ s (s-b) :Δ/ s (s-c) = 1:2:3
so,1/ (s-a) : 1/ (s-b) : 1/(s-c) = 1:2:3

s-a: s-b: s-c = 1:1/2 : 1/3

b+c-a : a+c-b : a+b -c = 1:1/2:1/3

now solve individually both pairs

Thanks
one year ago
mycroft holmes
272 Points
							
Let tan A = k, then tan B = 2k, and tan C = 3k.
 
In a triangle tan A+tan B +tan C = tan A tan B tan C and so we get k=1.
 
So tan A =1, tan B = 2, tan C = 3. so that 
 
So a2:b2:c2 = sin2A: sin2B:sin2C =
 
 \frac{1}{2}: \frac{2}{5}: \frac{3}{10} = 5:2:3
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 3,180 off

COUPON CODE: BCK2SKOOL


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 127 off

COUPON CODE: BCK2SKOOL

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details