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Grade: 11

                        

In triangle ABC ,SinA.SinB=ab/c square , then C = ??

3 years ago

Answers : (1)

Ravi malvia
37 Points
							
sinA.sinB = ab/c2
\tiny \because a=2RsinA , b=2Rsinb, c=2Rsinc 
put them in equation 
   sinA.sinB = (2RsinA.2RsinB)/(2RsinC)2
now remaining equation is below_
  sin2C = 1
  sinC = \tiny \pm1   \tiny \Leftrightarrow  C = 90 degree or  -270 degree
3 years ago
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