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in triangle ABC, sin3A.cos^3(B-C)+sin3B.cos^3(C-A)+sin 3C.cos^3(A-B)=

in triangle ABC, sin3A.cos^3(B-C)+sin3B.cos^3(C-A)+sin 3C.cos^3(A-B)=
 

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1 Answers

Harshit Singh
askIITians Faculty 5964 Points
2 months ago
Dear Student

Here is the link to your query:

https://www.askiitians.com/forums/Trigonometry/in-triangle-abc-sin3a-cos-b-c-sin3b-cos-c-a-sin_103025.htm

Thanks

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