In triangle ABC, if sinAcosB=1/4 and 3tanA=tanB, then cotsquareA is equal to?
In triangle ABC, if sinAcosB=1/4 and 3tanA=tanB, then cotsquareA is equal to?
Edited , 8 Years ago
Grade 12th Pass
Trigonometry> In triangle ABC, if sinAcosB=1/4 and 3tan...
2 AnswersDebraj Sarkar
Cot^2 A=√33tanA = tanB =>3sinAcosB=sinBcosAFrom question sinAcosB=1/4.Putting the value of SinACosB3/4=sinBcosA..............(i)1/4=sinAcosB..............(ii)Dividing (i) by (ii).....=>cotAtanB=3=>cotAcot(90-B)=3=>cotA*cotA=3=>cot^2(A)=3=>cotA=√3
anuridhi
3sinAcosB=sinBcosA
CosAsinB=3/4
Sin(A+B)=1
C=π/2,B=π/2-A
3tanA=tan(π/2-A)
3tanA=tan(π/2-A)
..................................
3=cot^2A
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