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In any triangle ABC show that the following tan (A+B-C/2)=cot (C) In any triangle ABC show that the followingtan (A+B-C/2)=cot (C)
A+ B = 180 – CA+ B -C = 180 – 2CA+ B -C / 2 = 180 – 2C / 2 = 90 – CHence tan (90 – C) = cot (C)
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