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question mark

in any triangle ABC, if tanA + tanB + tanC = 6 and tanAtanB=2 , then the values of tanA, tanB, tanC are
  1. ​1,2,3
  2. 2,1,3
  3. 1,2,0
  4. None of these

yash deshmukh , 6 Years ago
Grade
anser 1 Answers
Arun

Last Activity: 6 Years ago

 

tanA and tanB is either both positive or both negetive from tanAxtanB=2

tanA+tanB+tanC=tanA x tanB x tanC=6

 

thus tanC is 6.

hence tan A , tanB are 1, 2 or 2,1

 
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