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in any triangle ABC, if tanA + tanB + tanC = 6 and tanAtanB=2 , then the values of tanA, tanB, tanC are\t​1,2,3\t2,1,3\t1,2,0\tNone of these

yash deshmukh , 5 Years ago
Grade
anser 1 Answers
Arun

Last Activity: 5 Years ago

 

tanA and tanB is either both positive or both negetive from tanAxtanB=2

tanA+tanB+tanC=tanA x tanB x tanC=6

 

thus tanC is 6.

hence tan A , tanB are 1, 2 or 2,1

 

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